rfc3986 (2.0.0)
Published 2 years ago by guillem
Installation
pip install --extra-index-url https://git.guillemborrell.es/api/packages/guillem/pypi/simple rfc3986About this package
Validating URI References per RFC 3986
rfc3986
A Python implementation of RFC 3986_ including validation and authority
parsing.
Installation
Use pip to install rfc3986 like so::
pip install rfc3986
License
Apache License Version 2.0_
Example Usage
The following are the two most common use cases envisioned for rfc3986.
Replacing urlparse
To parse a URI and receive something very similar to the standard library's
``urllib.parse.urlparse``
.. code-block:: python
from rfc3986 import urlparse
ssh = urlparse('ssh://user@git.openstack.org:29418/openstack/glance.git')
print(ssh.scheme) # => ssh
print(ssh.userinfo) # => user
print(ssh.params) # => None
print(ssh.port) # => 29418
To create a copy of it with new pieces you can use ``copy_with``:
.. code-block:: python
new_ssh = ssh.copy_with(
scheme='https'
userinfo='',
port=443,
path='/openstack/glance'
)
print(new_ssh.scheme) # => https
print(new_ssh.userinfo) # => None
# etc.
Strictly Parsing a URI and Applying Validation
To parse a URI into a convenient named tuple, you can simply:
.. code-block:: python
from rfc3986 import uri_reference
example = uri_reference('http://example.com')
email = uri_reference('mailto:user@domain.com')
ssh = uri_reference('ssh://user@git.openstack.org:29418/openstack/keystone.git')
With a parsed URI you can access data about the components:
.. code-block:: python
print(example.scheme) # => http
print(email.path) # => user@domain.com
print(ssh.userinfo) # => user
print(ssh.host) # => git.openstack.org
print(ssh.port) # => 29418
It can also parse URIs with unicode present:
.. code-block:: python
uni = uri_reference(b'http://httpbin.org/get?utf8=\xe2\x98\x83') # ☃
print(uni.query) # utf8=%E2%98%83
With a parsed URI you can also validate it:
.. code-block:: python
if ssh.is_valid():
subprocess.call(['git', 'clone', ssh.unsplit()])
You can also take a parsed URI and normalize it:
.. code-block:: python
mangled = uri_reference('hTTp://exAMPLe.COM')
print(mangled.scheme) # => hTTp
print(mangled.authority) # => exAMPLe.COM
normal = mangled.normalize()
print(normal.scheme) # => http
print(mangled.authority) # => example.com
But these two URIs are (functionally) equivalent:
.. code-block:: python
if normal == mangled:
webbrowser.open(normal.unsplit())
Your paths, queries, and fragments are safe with us though:
.. code-block:: python
mangled = uri_reference('hTTp://exAMPLe.COM/Some/reallY/biZZare/pAth')
normal = mangled.normalize()
assert normal == 'hTTp://exAMPLe.COM/Some/reallY/biZZare/pAth'
assert normal == 'http://example.com/Some/reallY/biZZare/pAth'
assert normal != 'http://example.com/some/really/bizzare/path'
If you do not actually need a real reference object and just want to normalize
your URI:
.. code-block:: python
from rfc3986 import normalize_uri
assert (normalize_uri('hTTp://exAMPLe.COM/Some/reallY/biZZare/pAth') ==
'http://example.com/Some/reallY/biZZare/pAth')
You can also very simply validate a URI:
.. code-block:: python
from rfc3986 import is_valid_uri
assert is_valid_uri('hTTp://exAMPLe.COM/Some/reallY/biZZare/pAth')
Requiring Components
You can validate that a particular string is a valid URI and require
independent components:
.. code-block:: python
from rfc3986 import is_valid_uri
assert is_valid_uri('http://localhost:8774/v2/resource',
require_scheme=True,
require_authority=True,
require_path=True)
# Assert that a mailto URI is invalid if you require an authority
# component
assert is_valid_uri('mailto:user@example.com', require_authority=True) is False
If you have an instance of a ``URIReference``, you can pass the same arguments
to ``URIReference#is_valid``, e.g.,
.. code-block:: python
from rfc3986 import uri_reference
http = uri_reference('http://localhost:8774/v2/resource')
assert uri.is_valid(require_scheme=True,
require_authority=True,
require_path=True)
# Assert that a mailto URI is invalid if you require an authority
# component
mailto = uri_reference('mailto:user@example.com')
assert uri.is_valid(require_authority=True) is False
Alternatives
------------
- `rfc3987 <https://pypi.python.org/pypi/rfc3987/1.3.4>`_
This is a direct competitor to this library, with extra features,
licensed under the GPL.
- `uritools <https://pypi.python.org/pypi/uritools/0.5.1>`_
This can parse URIs in the manner of RFC 3986 but provides no validation and
only recently added Python 3 support.
- Standard library's `urlparse`/`urllib.parse`
The functions in these libraries can only split a URI (valid or not) and
provide no validation.
Contributing
------------
This project follows and enforces the Python Software Foundation's `Code of
Conduct <https://www.python.org/psf/codeofconduct/>`_.
If you would like to contribute but do not have a bug or feature in mind, feel
free to email Ian and find out how you can help.
The git repository for this project is maintained at
https://github.com/python-hyper/rfc3986
.. _RFC 3986: https://datatracker.ietf.org/doc/html/rfc3986/
.. _Apache License Version 2.0: https://www.apache.org/licenses/LICENSE-2.0
Requirements
Requires Python: >=3.7